Data Handlings
19, 25, 23, 20, 9, 20, 15, 10, 5, 16, 25, 20, 24, 12, 20
Find the mode and median of this data. Are they same?
Arranging in an ascending order
5, 9, 10, 12, 15, 16, 19, 20, 20, 20, 20, 23, 24, 25, 25
Mode,
Mode is the value which occurs most frequently.
So, mode is 20
Median,
Here n = 15, which is odd.
Where, n is the number of the students.
Median =Then, value on 8th position is = 20
So the median is 20.
Yes, both the values are same.
6, 15, 120, 50, 100, 80, 10, 15, 8, 10, 15
Find the mean, mode and median of this data. Are the three same?
Arranging in an ascending order
6, 8, 10, 10, 15, 15, 15, 50, 80, 100, 120
Mean,
Mean =Mode,
Mode is the value which occurs most frequently.
So, mode is 15
Median,
Here n = 11, which is odd.
Where, n is the number of players.
∴median =
Then, value of 6th term = 15
So the median is 15.
No, the value of these three are not same.
38, 42, 35, 37, 45, 50, 32, 43, 43, 40, 36, 38, 43, 38, 47
(i) Find the mode and median of this data.
(ii) Is there more than one mode?
Arranging in an ascending order, we get
32, 35, 36, 37, 38, 38, 38, 40, 42, 43, 43, 43, 45, 47, 50
(i)
Mode,
Mode is the value which occurs most frequently.
38 and 43 both occurs 3 times.
So, mode are 38 and 43.
Median,
Here n = 15, which is odd.
Where, n is the number of the students.
median =Then, value of 8th term = 40
So the median is 40.
(ii) Yes, there are 2 modes for the given weights of the students.
Arranging data in an ascending order, we get
= 12, 12, 13, 13, 14, 14, 14, 16, 19
Mode,
<14 occurs most of times.
So, mode is 14.
Median
Here n = 9, which is odd.
Where, n is the number of the students.
∴median =
Then, value of 5th term = 14
Hence, the median is 14.
(i) The mode is always one of the numbers in a data.
(ii) The mean is one of the numbers in a data.
(iii) The median is always one of the numbers in a data.
(iv) The data 6, 4, 3, 8, 9, 12, 13, 9 has mean 9.
(i)True.
(ii)False.
(iii)True.
(iv)False.