Question
A number when divided by 7 gives remainder 3. Find the remainder when its square is divided by 7. (NCERT Class 9/10 – Important)
Answer: Let n=7k+3. Then n²=(7k+3)²=49k²+42k+9=7(7k²+6k+1)+2. Remainder is 2.
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Question
Answer: Let n=7k+3. Then n²=(7k+3)²=49k²+42k+9=7(7k²+6k+1)+2. Remainder is 2.
Question
Answer: Let n=7k+3. Then n²=(7k+3)²=49k²+42k+9=7(7k²+6k+1)+2. Remainder is 2.