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Chapter 1:Knowing Our Number

Chapter 2:Whole Number

Chapter 3: Playing with Number

Chapter 4:Basic Gemetrical Idea

Chapter 5:Understanding Elementry Shapes

Chapter 6:Intergers

Chapter 7:Fraction

Chapter 8:Decimals

Chapter 9:Data Handling

Chapter 10:Mensuratin

Chapter 11:Algebra

Chapter 12:Ratio and Proportion

Chapter 13:Sysmmetry

NCERT Solutions For Class 6 Maths Chapter 1

Knowing your Number

NCERT Solutions For Class 6 Maths chapter 1 Exercise 1.3
Ex 1.3 class 6 Question 1.
Estimate each of the following using general rule:
(a) 730 + 998
(b) 796 – 314
(c) 12,904 + 2,888
(d) 28,292 – 21,496
Answer

(a) 730 + 998
Rounding off 730 = 700
Rounding off 998 = 1,000
total= 700 + 1000 = 1700

(b) 796 – 314
Rounding off 796 = 800
Rounding off 314 = 300
Total= 800 – 300 = 500

(c) 12,904 + 2,888
Rounding off 12,904 = 13000
Rounding off 2888= 3000
Total= 13000 + 3000 = 16000

(d) 28,292 – 21,496
Rounding off 28,292 = 28,000
Rounding off 21,496= 21,000
Total= 28,000 – 21,000 = 7,000

Ex 1.3 class 6 Question 2.
Give a rough estimate (by rounding off to nearest hundreds) and also a closer estimate (by rounding off to nearest tens):
(a) 439 + 334 + 4,317
(b) 1,08,734-47,599
(c) 8,325-491
(d) 4,89,348-48,365
Answer 2:

Rounding off to nearest hundreds

(a)439 + 334 + 4,317
Rounding off 439 = 400
Rounding off 334 = 300
Rounding off 4,317 = 4,300
Total=400 + 300 + 4300 =5,000

(b)(b) 1,08,734 – 47,599
Rounding off 1,08,734 =1,08,700
Rounding off 47,599=47,600
Total=1,08,700 – 47,600 = 61,100.

(c) 8325 – 491
Rounding off 8325 = 8300
Rounding off 491= 500
Total=8300 – 500 = 7800

(d) 4,89,348 – 48,365
Rounding off 4,89,348 = 4,89,300
Rounding off 48,365= 48,400
Total= 4,89,300 – 48,400 = 4,40,900

Rounding off to nearest tens

(a)439 + 334 + 4,317
439 + 334 + 4317 = 440 + 330 + 4320 = 5090.
total= 5,090

(b) 1,08,734 – 47,599
1,08,734 – 47,599 = 1,08,730 – 47,600 = 61,130.
Total= 61,130.
(c) 8325 – 491
8325 – 491 = 8330 – 490 = 7840.
Total=7840

(d) 4,89,348 – 48,365
4,89,348 – 48,365 = 4,89,350 – 48,370 = 4,40,980
Total= 4,40,980



Ex 1.3 class 6 Question 3.
Estimate the following products using general rule:
(a) 578 x 161
(b)5281 x 3491
(c) 1291 x 592
(d) 9250 x 29
Answer

Rounding off to nearest hundreds

(a) 578 x 161
Round of 578=600
Round of 161=200
product= 600 x 200 = 1,20,000

(b) 5281 x 3491
Round of 5281=5000
Round of 3491=3500
product= 5000 x 3000 = 1,50,00,000

Rounding off to nearest tens

(c) 1291 x 592
Round of 1291=1300
Round of 592=600
product= 1300 x 600 = 7,80,000

(d) 9250 x 29
Round of 9250=9000
Round of 29=30
product= 9000 x 30 = 2,70,000