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Chapter 1:Real Numbers

Chapter 2:Polynomials

Chapter 3:Pair of Linear Equations in Two Variables

Chapter 4:Quadratic Equations

Chapter 5: Arithmetic Progression

Chapter 6: Triangles

Chapter 7:Coordinate Geometry

Chapter 8: Introduction to Trigonometry

Chapter 9:Some Applications of Trigonometry

Chapter 10: Circles

Chapter 11:Constructions

Chapter 12:Area Related to Circles

Chapter 13:Surface Areas and Volumes

Chapter 14:Statistics

Chapter 15:Probability

NCERT Solutions class 10 maths chapter 14

Statistics

NCERT Solutions class 10 maths chapter 14 Exercise 14.1
Question 1
A survey was conducted by a group of students as a part of their environment awareness programme, in which they collected the following data regarding the number of plants in 20 houses in a locality. Find the mean number of plants per house.

Answer 1

We know the

Mean =
162 / 20
= 8.1

We use this method because value of fi and Xi is very small

Question 2

Consider the following distribution of daily wages of 50 workers of a factory


Find the mean daily wages of the workers of the factory by using an appropriate method

Answer 2

Mean x̄ ==NCERT Ex-14.1 class 10

150 + (20 ×
-12 / 50
)
= 150 – 4.8 = 145.20
The mean daily wage of the workers = 145.20
Question 3
The following distribution shows the daily pocket allowance of children of a locality. The mean pocket allowance is Rs 18. Find the missing frequency f.

Answer 3

Mean = =
(752+20f) / (752+20f)
)
Here mean= 18
⇒ 18 =
(752+20f) / (752+20f)
)
⇒ 18(44+f) = (752+20f)
⇒ 792+18f = 752+20f
⇒ 792+18f = 752+20f
⇒ 792 – 752 = 20f – 18f
⇒ 40 = 2f
⇒ f = 20
f = 20
Question 4
Thirty women were examined in a hospital by a doctor and the number of heart beats per minute were recorded and summarised as follows. Find the mean heart beats per minute for these women, choosing a suitable method.
NCERT Solution ex 14.1 class 10
Answer 4
NCERT Solution ex 14.1 class 10NCERT Solution ex 14.1 class 10

Mean = x̄ =NCERT Ex-14.1 class 10
A = 75.5 , h=3
= 75.5 + 3×(
4 / 30
)
= 75.5 +
4 / 30

= 75.5 + 0.4
= 75.9
Question 5
In a retail market, fruit vendors were selling mangoes kept in packing boxes. These boxes contained varying number of mangoes. The following was the distribution of mangoes according to the number of boxes.
NCERT Solution ex 14.1 class 10
Find the mean number of mangoes kept in a packing box. Which method of finding the mean did you choose?
Answer 5
NCERT Solution ex 14.1 class 10
Mean = x̄ = A +h
∑fidi / ∑fi

= 57 + 3(
75 / 400
)
= 57 + 0.1875 = 57.19
Question 6
The table below shows the daily expenditure on food of 25 households in a locality
Find the mean daily expenditure on food by a suitable method
NCERT Solution ex 14.1 class 10
Find the mean daily expenditure on food by a suitable method
Answer 6
NCERT Solution ex 14.1 class 10
Here a=225 , h=50
Mean = NCERT Solution ex 14.1 class 10
= 225+50(
-7 / 25
)
= 225-14
= 211
Question 7
To find out the concentration of SO2 in the air (in parts per million, i.e., ppm), the data was collected for 30 localities in a certain city and is presented below: NCERT Solution ex 14.1 class 10
Find the mean concentration of SO2 in the air
Answer 7
NCERT Solution ex 14.1 class 10
Mean = x̄ =NCERT Solution ex 14.1 class 10
=
2.96 / 30

= 0.099 ppm
Question 8
A class teacher has the following absentee record of 40 students of a class for the whole term. Find the mean number of days a student was absent NCERT Solution ex 14.1 class 10
Answer 9
NCERT Solution ex 14.1 class 10
Mean = NCERT Solution ex 14.1 class 10
=
499 / 40

= 12.48
Question 9
The following table gives the literacy rate (in percentage) of 35 cities. Find the mean literacy rate.
NCERT Solution ex 14.1 class 10
Answer 9
NCERT Solution ex 14.1 class 10NCERT Solution ex 14.1 class 10
Mean = NCERT Solution ex 14.1 class 10
here a=70 , h =10
= 70 + 10 x(
-2 / 35
) = 69.42